Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
19.5k views
in Chemistry by (49.7k points)

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

1 Answer

+1 vote
by (49.6k points)
selected by
 
Best answer

300 g of 25% solutions contains solute = 75 g 

400 g of 40% solution contains solute = 160 g. 

Total solute = 160 + 75 = 235 g 

Total solution=300 + 400 = 700 g 

% of solute in final solution = \(\frac{235}{700}\) × 100 = 33.5% 

% of water in the final solution = 100 - 33.5 = 66.5%

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...