300 g of 25% solutions contains solute = 75 g
400 g of 40% solution contains solute = 160 g.
Total solute = 160 + 75 = 235 g
Total solution=300 + 400 = 700 g
% of solute in final solution = \(\frac{235}{700}\) × 100 = 33.5%
% of water in the final solution = 100 - 33.5 = 66.5%