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An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?

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Vapour pressure of pure water at boiling point (P°) = 1 atm = 1.013 bar 

vapour pressure of solution (ps) = 1.004 bar 

Mass of solute = (w2) = 2g 

Mass of solution = 100 g 

Mass of solvent = 98g 

Applying Roault’s law for dilute solution (being 2%)

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