We know that the given equations are
2x + 3y = 14… equation (i)
2x – 3y = 2… equation (ii)
Now, let us square both the equations and subtract equation (ii) from equation (i), we get,
(2x + 3y)2 – (2x – 3y)2 = (14)2 – (2)2
4x2 + 9y2 + 12xy – 4x2 – 9y2 + 12xy = 196 – 4
24xy = 192
xy = 8
∴ The value of xy is 8.