Given: Δ ABC and AD bisects ∠A, meeting side BC at D. And AB = 5.6 cm, AC = 6 cm, and DC = 3 cm.
Required to find: BC
Since, AD is the bisector of ∠A meeting side BC at D in Δ ABC
⇒ \(\frac{AB}{AC}\) = \(\frac{BD}{DC}\)
\(\frac{5.6}{6}\) = \(\frac{BD}{3}\)
BD = \(\frac{5.6}{2}\) = 2.8 cm
And, we know that,
BD = BC – DC
2.8 = BC – 3
∴ BC = 5.8 cm