Given: Δ ABC and AD bisects ∠A, meeting side BC at D. And AB = 5.6 cm, BC = 6 cm, and BD = 3.2 cm.
Required to find: AC
Since, AD is the bisector of ∠A meeting side BC at D in Δ ABC
⇒ \(\frac{AB}{AC}\) = \(\frac{BD}{DC}\)
\(\frac{5.6}{AC}\) = \(\frac{3.2}{DC}\)
And, we know that
BD = BC – DC
3.2 = 6 – DC
∴ DC = 2.8 cm
⇒ \(\frac{5.6}{AC}\) = \(\frac{3.2}{2.8}\)
AC = \(\frac{(5.6 \times 2.8)}{3.2}\)
∴ AC = 4.9 cm
