Let’s assume the length of ladder to be, AD = BE = x m
So, in ∆ACD, by Pythagoras theorem
We have,
AD2 = AC2 + CD2
⇒ x2 = 82 + 62 … (i)
Also, in ∆BCE, by Pythagoras theorem
BE2 = BC2 + CE2
⇒ x2 = BC2 + 82 … (ii)
Compare (i) and (ii)
BC2 + 82 = 82 + 62
⇒ BC2 + 62
⇒ BC = 6 m
Therefore, the tip of the ladder reaches to a height of 6 m.