Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.8k views
in Statistics by (62.7k points)

A company manufactures car tyres. Their average life is 40,000 km and standard deviations 5,000 km. A change in the production process is believed to result in a better product. A test sample of 100 new tyres has mean life of 41,000 km. Can you conclude at 1% L.O.S. that the new product gives better result?

1 Answer

0 votes
by (57.2k points)
selected by
 
Best answer

Given: µ = 40,000, σ = 5,000, n = 100, x̄ =41,000, α = 1% .
H0 : Mean lif eof tyres is 40,000 kms (i.e., µ = 40,000)
H1 : Mean life of tyres is mroe than 40,000 kms (better result) (i.e., µ > 40,000) {upper tail test)

Under Hthe test statistics is:

At α = 1% the lower tail critical value k = 2.33
Here zcal lies in acceptance region (A.R) H0 is accepted
∴ Ho is accepted.
Conclusion: Mean life of tyres is 40,000 kms.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...