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Maximise z = 5x + 3y  subject to  3x + 5y ≤ 15  5x + 2y ≤ 10 

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in Linear Programming by (65.5k points)

Maximise z = 5x + 3y 

subject to 

3x + 5y ≤ 15 

5x + 2y ≤ 10 

x ≥ 0,7 ≥ 0

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1 Answer

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Best answer

Consider 3x + 5y = 15

Plot the lines on the graph. 

O ABC is the solution region.

X is maximum at B (\(\frac{20}{19}, \frac{45}{19}\))

Zmax = \(\frac{235}{19}\) = 12.37

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