Given: n = 1000; x = 470; P = \(\frac{x}{n}\) = \(\frac{470}{100}\) 0.47 and P0/P –population proportion = 0.5;
Q0 = 1 – p0 = 0.5 [male and female are in equal in proportion]
H0: Male and female are in equal proportion [P0 = 0.5]
H1: Male and female are not in equal proportion [p0 ≠ 0.5]
under H0, the test statistic is:-
At α = 0.5 the two tail critical values are ±1.96 Here zcal lies in A.R.
∴ H0 is accepted.
Conclusion: P0 = 0.5 [male and female are in equal proportion]