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in Laws of Motion and Friction by (340 points)

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1 Answer

+1 vote
by (275 points)

When we resolve the force 10N making an angle 60with the horizontal we get

F'=10 cos60=10×(√3)/2=5(√3)N ,this force is acting along X axis 

We have another force F acting along Xaxis that is 5N but it is in opposite direction so 

the resultant force will be

R=F'-F=5(√3)-5 (because F <F')

Since the above resultant R is not zero therefore acceleration is along X axis

Extra Info

The acceleration along X axis can be taken as +ve or -ve because if we take the 

direction of force 5N as +ve X axis direction the the acceleration is in -'ve direction.

But if we take direction of force 5(√3)N as +ve X axis direction then acceleration is +ve.

Now to find acceleration 

Ftotal=R

Ma=5(√3)-5

a=5 [ (√3)-1]/√3                  (given M=(√3) kg)

After calculation of acceleration it is approximately

a=2.11 m/s2

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