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0 votes
11.2k views
in Kinematics by (340 points)
edited by

If a ball is projected vertical upward from ground such that total distance traveled is 3.6 times of distance travel by the ball in 1st second, then find time of flight of ball?

1 Answer

+1 vote
by (275 points)
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Best answer

Let initial velocity be u 

Total height,H= u2/2g

Total distance the ball travel is u2/g

Total time of flight,T=2u/g

Distance in 1 second

s=u-(g/2)

As given in question

3.6s=2H

3.6 [u-(g/2)]=2×u2/2g 

3.6 [u-5]=u2/10

36u-180=u

When we solve the above equation we get

u=30 or 6

T=2×30/10=6s

           Or

T=2×6/10=1.2S

From the given options the correct answer is T=6s

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