P_{1} = I^{2}R, P_{2} = (2I)^{2}R = 4I^{2}R (as 100% increase in current means that current becomes 2I).

Increase in power dissipated

= P_{2} - P_{1} = 4i^{2}R - I^{2}R = 3i^{2}R = 3P_{1}

% age increase in power dissipated = \(\frac{3P_1}{P1} \times 100\) = 300%