Question

If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), find the increase in power dissipated.

Answer 1

P₁ = I²R, P₂ = (2I)²R = 4I²R (as 100% increase in current means that current becomes 2I).

Increase in power dissipated

= P₂ - P₁ = 4i²R - I²R = 3i²R = 3P₁

% age increase in power dissipated = \(\frac{3P_1}{P1} \times 100\) = 300%