m_{a} = 80%

= \(\frac{80}{100}\)

= 0.8

P_{T} = 2200 W

P_{T} = P_{c}(1 + \(\frac{m_a^2}{2}\))

2200 = P_{c}[1 + \(\frac{(0.8)^2}{2}\)]

2200 = P_{c}[1 + 0.32]

P_{c} = \(\frac{2200}{1.32}\)

P_{c }= 1666W

P_{T} = P_{c }+ Power in the sidebands

Power in two sidebands = P_{T} - P_{c}

= 2200 - 1666W

= 534W

Power in each sideband = \(\frac{534}{2}\)

= 267W