Sarthaks Test
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Determine the power content of the carrier an each of side bands of an AM wave having a percent modulation of 80% and a total power of 2200W.

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Best answer

ma = 80%

\(\frac{80}{100}\)

= 0.8

PT = 2200 W

PT = Pc(1 + \(\frac{m_a^2}{2}\))

2200 = Pc[1 + \(\frac{(0.8)^2}{2}\)]

2200 = Pc[1 + 0.32]

Pc\(\frac{2200}{1.32}\)

Pc = 1666W

PT = Pc + Power in the sidebands

Power in two sidebands = PT - Pc

= 2200 - 1666W

= 534W

Power in each sideband = \(\frac{534}{2}\)

= 267W

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