P_{T }= P_{c} + P_{LSB} + P_{USB}

2500 = P_{c} + 300 + 300

P_{c} = 2500 - 600

P_{c} = 1900W

P_{T} = P_{c}(1 + \(\frac{m_a^2}{2}\))

2500 = 1900[1 + \(\frac{m_a^2}{2}\)]

\(\frac{2500}{1900}\) = 1 + \(\frac{m_a^2}{2}\)

1.315 - 1 = \(\frac{m_a^2}{2}\)

\(m_a^2\) = 2(0.315) = 0.631

m_{a} = \(\sqrt{0.631}\)

m_{a} = 0.794

= 0.794 x 100

= 79.4%