f_{c} = 93.2 MHz

f_{m} = 5kHz.Δf = 50kHz

a) Carrier swing = 2Δf

= 2(50kHz) = 100kHz

b) f_{max} = f_{c} + Δf

= 93.2 x 10^{6} + 5 x 10^{3}

= 10^{3}(93.2 x 10^{3} + 5)

= 93.205 MHz

f_{min }= f_{c} - Δf

= 93.2 x 10^{6} - 5 x 10^{3}

= 10^{3}(93.2 x 10^{3} - 5)

= 93.195 MHz

c) m = \(\frac{\Delta f}{f_m}\)

= \(\frac{50}{5}\)

= 10