Sarthaks Test
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A 93.2 MHz carrier is frequency modulated by a 5 kHz sinewave. The resultant FM signal has a frequency deviation of 50kHz.

a). Find the carrier swing of the FM wave.

b). Determine highest and lowest frequencies attained by modulated signal.

c). What is modulation index of FM wave

1 Answer

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fc = 93.2 MHz

fm = 5kHz.Δf = 50kHz

a) Carrier swing = 2Δf

= 2(50kHz) = 100kHz

b) fmax = fc + Δf

= 93.2 x 106 + 5 x 103

= 103(93.2 x 103 + 5)

= 93.205 MHz

fmin = fc - Δf

= 93.2 x 106 - 5 x 103

= 103(93.2 x 103 - 5)

= 93.195 MHz

c) m = \(\frac{\Delta f}{f_m}\)

\(\frac{50}{5}\)

= 10

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