Question

Five resistors are connected in a circuit as shown in figure. Find the ammeter reading when the circuit is closed.

Answer 1

R₁ and R₂ are in series,

R = R₁ + R₂ 

= 3+ 3 = 6\(\Omega\)

This is in parallel with R₃, so

\(\frac{1}{R_P} = \frac{1}{R} + \frac{1}{R_3}\)

= \(\frac{1}{6} + \frac{1}{3} = \frac{1}{2}\)

⇒ R_P = 2\(\Omega\)

R₄, R_P and R₅ are in series,

R = R₄ + R_P + R₅ 

= 0.5 + 2 + 0.5

= 3\(\Omega\)

Then current,

I = \(\frac{1}{R} = \frac{3}{3}\) = 1A