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If 4 times the 4th term of an AP is equal to 18 times the 18th term, then find the 22nd term.

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Let the first term and common difference be a and d

According to the question, 

4(a + 3d) = 18 × (a + 17d)

4a + 12d = 18a + 306d 

14a + 294d = 0 

a + 21d = 0

a22 = a + 21d 

= 0

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