Given as
Let us find the f(1), f(–1), f(0) and f(2).
If x > 0, f (x) = 4x + 1
By substituting x = 1 in the above equation, we get
f (1) = 4(1) + 1
= 4 + 1
= 5
If x < 0, f(x) = 3x – 2
By substituting x = –1 in the above equation, we get
f (–1) = 3(–1) – 2
= –3 – 2
= –5
If x = 0, f(x) = 1
By, substituting x = 0 in the above equation, we get
f(0) = 1
If x > 0, f(x) = 4x + 1
By substituting x = 2 in the above equation, we get
f(2) = 4(2) + 1
= 8 + 1
= 9
Thus f(1) = 5, f(–1) = –5, f(0) = 1 and f(2) = 9.