Question

Write the first terms of the sequences whose nth term are:

a_n = 2n² – 3n + 1

Answer 1

The given sequence whose a_n = 2n² – 3n + 1

To get the first five terms of the sequence, put n = 1, 2, 3, 4, 5.

And, we get

a₁ = 2.1² – 3.1 + 1 = 2 – 3 + 1 = 0

a₂ = 2.2² – 3.2 + 1 = 8 – 6 + 1 = 3

a₃ = 2.3² – 3.3 + 1 = 18 – 9 + 1 = 10

a₄ = 2.4² – 3.4 + 1 = 32 – 12 + 1 = 21

a₅ = 2.5² – 3.5 + 1 = 50 – 15 + 1 = 36

∴ The required first five terms of the sequence are 0, 3, 10, 21, 36.