Given:
Mass of water, m = 10 g = 0.01 kg
Pressure, P = 105 Pa
Specific heat capacity of water, c = 1000 J/Kg °C
Latent heat, L = 2.25×106 J/Kg
Δt=Change in temperature of the system=100°C=373 K
∆t=Change in temperature of the system=100°C=373 K
∆Q = Heat absorbed to raise the temperature of water from 0°C to 100°C + Latent heat for conversion of water to steam