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in Indefinite Integral by (65.3k points)

Evaluate: \(\int\frac{x^2 + 3x - 2}{x^2 - 4x - 12}dx\)

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\(\int\frac{x^2 + 3x - 2}{x^2 - 4x - 12}dx\)

Let 7x + 10 = A(x + 2) + B(x – 6) 

put x = 6 42 + 10 = A(6 + 2) + B(0); 52 = 8A ⇒ A = \(\frac{B}{2}\) 

put x = -2 -14 + 10 = A(0) + B(-2 -6)

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