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Evaluate:  \(\int_1^2\frac{2x + 5}{(x^2 + 5x + 3)^2}dx\)

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Evaluate: \(\int_1^2\frac{2x + 5}{(x^2 + 5x + 3)^2}dx\)

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\(\int_1^2\frac{2x + 5}{(x^2 + 5x + 3)^2}dx\)

put x2 + 5x + 3

(2x + 5)dx = dt

If x = 1, t = 1 + 5 + 3 = 9

If x = 2, t = 4 + 10 + 3 = 17

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