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in Definite Integrals by (65.5k points)

If the marginal cost of a firm is f'(x) = 10 + 6x – 6x2 where x is the output find the total cost assuming that the fixed cost is Rs 125.

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Given MC = f'(x) = 10 + 6x – 6x2, C = 125, TC = ? 

TC = C(x) = ∫MCdx = ∫(10 +6x – 6x2)dx = 10x + \(\frac{6x^2}{2} - \frac{6x^3}{3}\)+ C 

Total cost = 10x + 3x2 – 2x3 + 125.

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