Given an A.P. whose nth term is given by yn = 9 – 5n
To find the sum of the n terms of the given A.P., using the formula,
Sn = \(\frac{n(a \,+\, l)}{2}\)
Where, a = the first term l = the last term.
Putting n = 1 in the given yn, we get
a = 9 – 5(1) = 9 – 5 = 4
For the last term (l), here n = 15
a15 = 9 – 5(15) = -66
So, Sn = \(\frac{15(4 \,–\, 66)}{2}\)
= 15 x (-31)
= -465
Therefore, the sum of the 15 terms of the given A.P. is S15 = -465