Given,
First term of the A.P is 1505 and
S14 = 1505
We know that, the sum of first n terms is
Sn = \(\frac{n}{2}\)(2a + (n − 1)d)
So,
S14 = \(\frac{14}{2}\)(2(10) + (14 − 1)d) = 1505
7(20 + 13d) = 1505
20 + 13d = 215
13d = 215 – 20
d = \(\frac{195}{13}\)
d =15
Thus, the 25th term is given by
a25 = 10 + (25 -1)15
= 10 + (24)15
= 10 + 360
= 370
Therefore, the 25th term of the A.P is 370.