Given,
PA and PB are the tangents drawn from a point P outside the circle with centre O.
CD is another tangents to the circle at point E which intersects PA and PB at C and D respectively.
PA = 14 cm
PA and PB are the tangents to the circle from P
So, PA = PB = 14 cm
Now, CA and CE are the tangents from C to the circle.
CA = CE ….(i)
Similarly, DB and DE are the tangents from D to the circle.
DB = DE ….(ii)
Now, perimeter of ∆PCD
= PC + PD + CD
= PC + PD + CE + DE
= PC + CE + PD + DE
= PC + CA + PD = DB {From (i) and (ii)}
= PA + PB
= 14 + 14
= 28 cm