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A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day. Rs. 250 for the second day. Rs. 300 for the third day. etc.. the penalty for each succeeding day being Rs. 50 more than for the preceding day. How much money the contractor has to pay as penalty. If he has delayed the work by 30 days?

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Penalty for the 1st Day 2nd day 3rd day … 30th day 

Rs. 200 Rs. 250 Rs. 300 Rs.? 

200 + 250 + 300 + 30 days 

a = 200, d = 250 – 200 = 50, n = 20, 

S30 = ?

= 15[400 + 29 × 50] 

= 15 [400 + 1450] 

= 15 × 1850 

∴ S30 = Rs. 27750.

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