Let the initial height of the tree be AC.
And, due to storm the tree is broken at B.
Let the bent portion of the tree be AB = x m and the remaining portion BC = h m
So, the height of the tree AC = (x + h) m
And, given DC = 8m
Now, in ΔBCD
tan 30o = BC/DC
1/√3 = h/8
h = 8/√3
Next, in ΔBCD
cos 30o = DC/BD
√3/2 = 8/x
x = 16/√3 m
So, x + h = 16/√3 + 8/√3
= 24/√3 = 8√3
Therefore, the height of the tree is 8√3 m.