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A bulb with rating 250V, 100W is connected to a power supply of 220V situated 10m away using a copper wire of area of cross-section 5mm2. How much power will be consumed by the connecting wires? Resistivity of copper = 1.7 x 10-8Ω-m.

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1 Answer

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by (147k points)

V = 250V

P = 100w

R = V2/P = (250)2/100 = 625Ω

Resistance of wire R 

∴ The effect in resistance = 625.034Ω

 The current in the conductor

 The power supplied by one side of connecting wire

 The total power supplied

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