Given numbers are 1, 2, 2, 3, 3, 3, 4, 4, 4, 4
Total number of possible outcomes = 10
= \(\frac{30}{10}\)
= 3
Now, let E be the event of getting 3.
Number of favourable outcomes = 3 {3, 3, 3}
P(E) = Number of favourable outcomes/ Total number of outcomes
P(E) = 3/10
Therefore, the probability that a number selected at random will be the average is 3/10.