Question

The potential difference between two terminals of an electric iron is 220 V and the current flowing through its element is 5A. Calculate the resistance and wattage of the electric iron.

Answer 1

Given V = 220 V, I = 5A

∴ resistance, A = \(\frac{V}{I}\) = \(\frac{220}{5}\Omega\) = \(44\Omega\)

W.K.T. Power = V × I

= 220 × 5 = 1100 W.