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A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is

(i) Red or white (ii) Not black (iii) Neither white nor black

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Best answer

Total number of balls = 8 + 6 + 4 = 18

Total no. of possible outcomes =18

(i)  Let E = Event of getting red or white ball

No. of favourable outcomes = 14 (8 red balls + 6 white balls)

Probability, P(E) = Number of favourable outcomes/ Total number of outcomes

P(E) = 14/18

P(E) = 7/9

(ii)  Let E = Event of getting a black ball

Number of favourable outcomes = 4 (4 black balls)

P(E) = 4/18

P(E) = 2/9

Then,
\(\overline E\)= Event of not getting a black ball

(iii)  Let E = event of getting neither a white nor a black ball

No. of favourable outcomes = 18 – 6 – 4

= 8(Total balls – no. of white balls – no. of black balls)

Probability, P(E) = Number of favourable outcomes/ Total number of outcomes

P(E) = 8/18 = 4/9

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