Question

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red (ii) not red

Answer 1

Given,

A bag contains 3 red and 5 black balls.

So, the total no. of possible outcomes = 8 (3 red + 5 black)

(i) Let E = event of getting red ball.

No. of favourable outcomes = 3 (as there are 3 red)

Probability, P(E) = Number of favourable outcomes/ Total number of outcomes

P(E) = 3/8

(ii)  Let

\(\overline E\) = event of getting no red ball.

From the previous question we already have P(E) = 3/8