Let us consider the LHS
√[(1 – cos 2x)/(1 + cos 2x)]
As we know that cos 2x = 1 – 2 sin2 x
= 2 cos2 x – 1
Therefore,
√[(1 – cos 2x)/(1 + cos 2x)] = √[(1 – (1 – 2sin2 x))/(1 + (2cos2x – 1))]
= √[(1 – 1 + 2sin2 x)/(1 + 2cos2 x – 1)]
= √[2 sin2 x/2 cos2 x]
= sin x/cos x
= tan x
= RHS
Thus proved.