Question

In the accompanying diagram, a fair spinner is placed at the centre O of the circle. Diameter AOB and radius OC divide the circle into three regions labelled X, Y and Z.? If ∠BOC = 45°. What is the probability that the spinner will land in the region X?

Answer 1

Given,

∠BOC = 45°

∠AOC = 180 – 45 = 135° [Linear Pair]

Area of circle = πr²

Area of region x = θ/360 × πr²

= 135/360 × πr²

= 3/8 × πr²

The probability that the spinner will land in the region

x = \(\frac{3}{8}\)

Therefore, the probability that the spinner will land in region x is \(\frac{3}{8}\).