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Molar mass of Na2CO3 = 2 × 23 + 12 × 3 × 16 = 106 g/mol.
0.50 mol Na2CO3 means 0.50 × 106 = 53 g.
0.50 mol Na2CO3 means 0.50 mol i.e. 53 g of Na2CO3 are present in 1 L of the solution.

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