∆50 or (y – 1)5 = y5 – 5y4 + 10y3 – 10y2 + 5y1 – y0 = 0
∆60 or (y – 1)6 = y6 – 6y5 + 15y4 – 20y3 + 15y2 – 6y1 + y0 = 0
Write the formula to find the value of ‘x’ in finding the missing value of ‘y’ using Newton’s method of interpolation.
\(\frac {\textit{The (x) value to be interpolated -The value of X at the origin}}{\textit{The difference between the two adjoining valules (of X)}} \)
Write down the Newton’s formula for interpolation.
