Let X and Y be year and production.
Since the known values of ‘Y’ are four, the fourth order leading differences will be
zero, i.e. (y- 1)4 = 0 or Δ4 = 0
(y – 1 )4 = y4 – 4y3 + 6y2 – 4y1 + y0 = 0 (i)
and the second equation can be obtained by increasing the suffixes of each term of ‘Y’ by one, keeping the. coefficients same;
we get
y5 – 4y4 + 6y3 – 4y2 + y1 = 0 ……(ii)
From equation (i) 52 – 4y3 + 6 (28) – 4(18) + 8 = 0
52 – 4y3 + 168 -72 + 8 = 0
So, by simplifying, – 4y3 = – 156
∴ y3 = 39 ie. Production for the year 2010 is 139 (tons).
From (ii) y5 – 4y4 + 6y3 – 4y2 + y1 = 0; Here y3 = 39
y5 – 4 x 52 + 6 x (39) – 4 x 28 + 18 = 0
y5 – 208 + 234 – 112 + 18 = 0
∴ y5 = 68 i.e. the production for the year 2012 is 68(tons)