(i) Total area of 9 circular designs each of radius 7 cm
(ii) All the circles touches externally.
∴ Sum of the diameter of 3 circles in first Row
= 14 + 14 + 14 = 42 cm.
∴ Length of each side of square ABCD,
a = 42 cm.
∴ Area of square ABCD = a2
= (42)2 = 1764 sq.cm.
Area of remaining part of handkerchief:
= Area of square – Area of 9 circles.
= 1764 – 1386
= 378 sq.cm.