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+1 vote
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in Physics by (100 points)
What will be the equilibrium temperature when 150 g of I've is at 0°C with 200 g  of water at 50°C
by (194 points)
I'll assume that you'd written ice. So, you can always use "Heat loss = Heat gain" (magnitudes), in case of mixing stuffs at different temperatures.

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1 Answer

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by (5.0k points)

Ice at 0°C has a total latent heat of

Q= m x L = 150 x 80 = 12000 cal.

Now for water to come at 0°C and it's state to remain as water, we need to remove heat from it which is given by,

Q = m x Cp x (∆T) =  200 x 1 x  50 = 10000 cal.

So, we can see that

Heat released by water to reach from 50°C to 0°C = heat required by ice to melt into water at 0°C.

So, the ice will melt to water and its temperature will be 2000°C.

Hence, the final state would be water at 2000°C.

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