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in Coordinate Geometry by (65.2k points)

Find the values of ‘y’ for which the distance between the points P(2, -3) and Q (10, y) is 10 units.

1 Answer

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If distance between P and Q, PQ = 10 units, then y = ?

By Squaring on both sides,

y2 + 6y + 73 = 100 

y2 + 6y + 73 – 100 = 0 

y2 + 6y – 27 = 0 

y2 + 9y – 3y – 27 = 0

y (y + 9) – 3(y + 9) = 0 

(y + 9) (y – 3) = 0 

If y + 9 = 0 then OR y – 3 = 0 then 

y = -9 y = 0 

∴ y = -9 OR +3.

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