Let x be the number of throws results in multiple of 3 is a Binomial variate with n = 4,p = p
[a die thrown results in multiple of 3]
= \(\frac{2}{6}\) = \(\frac{1}{3}\)
∴ q =\(\frac{2}{3}\)
Then, mean = np = 4 x \(\frac{1}{3}\)= 1.33.
Variance = npq = 4 x\(\frac{1}{3}\) x\(\frac{2}{3}\) = 0.889.