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in Coordinate Geometry by (65.2k points)

Find a relation between ‘x’ and ‘y’ such that the point (x, y) is equidistant from the point (3, 6) and (-3, 4).

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Best answer

A (3, 6) = A (x1, y1) AP = PB. 

P(x, y) 

Let B(-3, 4) = B(x2, y2).

Here, AP = PB. 

∴ AP2 = PB2

x2 – 6x + y2 – 12y + 45 = x2 + y2 + 6x – 8y + 25 

-6x – 6x – 12y + 8y = 25 – 45 

– 12x – 4y = -20 

12x + 4y = 20 

∴ 3x + y = 5 

∴ 3x + y – 5 = 0

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