Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
30.0k views
in Physics by (60.8k points)

An electron having a kinetic energy of 100eV circulates in a path of radius 10cm in a magnetic field. Find the magnetic field and the number of revolutions per second made by the electron.

1 Answer

0 votes
by (150k points)
selected by
 
Best answer

KE = 100ev = 1.6 × 10–17J

(1/2) × 9.1 × 10–31 × V2 = 1.6 × 10–17J

=> V2 = (1.6 x 10-17 x 2)/(9.1 x 10-31) = 0.35 x 1014

or, V = 0.591 × 107m/s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...