First probability term: P(x = 0) = 0.0337
ie., 4co p0 q4 – 0 = 0.0337
1. 1. q4 = 0.03337 → (1)
Second probability term :
P(x = 1) = 0.18
i.e., 4c1 p1 q4 – 1 = 0.18.
4 p q3 = 0.18 → (2)
(2) ÷ (1)
= (1 – p) 1.3353
p = 1.3353 – 1.3353 p
p + 1.3353 p= 1.3353
2.3353 p= 1.3353
P = \(\frac{1.3353}{2.3353}\) = 0.5718