Question

A particle of mass m and charge q is projected into a region having a perpendicular magnetic field B. Find the angle of deviation (figure 34-E14) of the particle as it comes out of the magnetic field if the width d of the region is very slightly smaller than

(a) mv/qB (b) mv/2qB (c) 2mv/qB.

Answer 1

Mass of the particle = m, Charge = q, Width = d

(a) If d = mV/qB

The d is equal to radius. θ is the angle between the

radius and tangent which is equal to π/2 (As shown in the figure)

(b) If ≈ mV/2qB distance travelled = (1/2) of radius

Along x-directions d = V_Xt [Since acceleration in this direction is 0. Force acts along j  directions]

Looking into the figure, the angle between the initial direction and final direction of velocity is π.