Mass of the particle = m, Charge = q, Width = d
(a) If d = mV/qB
The d is equal to radius. θ is the angle between the
radius and tangent which is equal to π/2 (As shown in the figure)
(b) If ≈ mV/2qB distance travelled = (1/2) of radius
Along x-directions d = VXt [Since acceleration in this direction is 0. Force acts along j directions]
Looking into the figure, the angle between the initial direction and final direction of velocity is π.