Question

Find the area of the quadrilateral whose vertices, taken in order, are (-4, -2), (-3, -5), (3, -2) and (2, 3)

Answer 1

Area of quadrilateral ABCD = ? 

In the quadrilateral ABCD, diagonal AC is drawn which divides ∆ABC, ∆ACD. Sum of these triangles is equal to the Area of quadrilateral. 

(i) Now, Area of ∆ABC :

∴ Area of quadrilateral: 

= Area of ∆ABC + Area of ∆ACD = 10.5 + 17.5 = 28 sq. units. 

∴ Area of quadrilateral ABCD = 28 sq.units.