Given,
50 circular plates each with diameter 14 cm
Radius of circular plates = 7cm
Thickness of plates = 0.5 cm
As these plates are one above the other, the total thickness of all the plates = 0.5 x 50 = 25 cm
So, the total surface area of the right circular cylinder formed = 2πr × h + 2πr2
= 2πr (h + r)
= 2(22/7) x 7 x (25 + 7)
= 2 x 22 x 33 = 1408 cm2
Therefore, the total surface area of the cylinder is 1408 cm2.