LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
19.1k views
in Physics by (60.2k points)

Figure (34-E17) shows a convex lens of focal length 12cm lying in a uniform magnetic field B of magnitude 1.2T parallel to its principal axis. A particle having a charge 2.0 x 10-5C and mass 2.0 x 10-5kg is projected perpendicular to the plane of the diagram with a speed of 4.8m/s. The particle moves along a circle with its centre on the principal axis at a distance of 18cm from the lens. Show that the image of the particle goes along a circle and find the radius of that circle.

1 Answer

0 votes
by (148k points)
selected by
 
Best answer

The object will make a circular path, perpendicular to the plance of paper

Let the radius of the object be r

Here object distance K = 18cm.

Let the radius of the circular path of image = r'

So magnification = v/u = r'/r(magnetic path = image height/object height)

Hence radius of the circular path in which the image moves is 8cm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...